12n-(n+3)=-11+2(r-5)

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Solution for 12n-(n+3)=-11+2(r-5) equation:


Simplifying
12n + -1(n + 3) = -11 + 2(r + -5)

Reorder the terms:
12n + -1(3 + n) = -11 + 2(r + -5)
12n + (3 * -1 + n * -1) = -11 + 2(r + -5)
12n + (-3 + -1n) = -11 + 2(r + -5)

Reorder the terms:
-3 + 12n + -1n = -11 + 2(r + -5)

Combine like terms: 12n + -1n = 11n
-3 + 11n = -11 + 2(r + -5)

Reorder the terms:
-3 + 11n = -11 + 2(-5 + r)
-3 + 11n = -11 + (-5 * 2 + r * 2)
-3 + 11n = -11 + (-10 + 2r)

Combine like terms: -11 + -10 = -21
-3 + 11n = -21 + 2r

Solving
-3 + 11n = -21 + 2r

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 11n = -21 + 3 + 2r

Combine like terms: -3 + 3 = 0
0 + 11n = -21 + 3 + 2r
11n = -21 + 3 + 2r

Combine like terms: -21 + 3 = -18
11n = -18 + 2r

Divide each side by '11'.
n = -1.636363636 + 0.1818181818r

Simplifying
n = -1.636363636 + 0.1818181818r

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