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12m^2+11m-15=0
a = 12; b = 11; c = -15;
Δ = b2-4ac
Δ = 112-4·12·(-15)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-29}{2*12}=\frac{-40}{24} =-1+2/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+29}{2*12}=\frac{18}{24} =3/4 $
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