12k(2k+11)=12(2k+12k)

Solution for 12k(2k+11)=12(2k+12k) equation:

12k(2k+11)=12(2k+12k)

We move all terms to the left:

12k(2k+11)-(12(2k+12k))=0

We add all the numbers together, and all the variables

12k(2k+11)-(12(+14k))=0

We multiply parentheses

24k^2+132k-(12(+14k))=0


We calculate terms in parentheses: -(12(+14k)), so:

12(+14k)

We multiply parentheses

168k

Back to the equation:

-(168k)


We add all the numbers together, and all the variables

24k^2-36k=0

a = 24; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·24·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*24}=\frac{0}{48}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*24}=\frac{72}{48}
=1+1/2
$