12j-6(2j-1)=-2j(j-3)

Solution for 12j-6(2j-1)=-2j(j-3) equation:

12j-6(2j-1)=-2j(j-3)

We move all terms to the left:

12j-6(2j-1)-(-2j(j-3))=0

We multiply parentheses

12j-12j-(-2j(j-3))+6=0


We calculate terms in parentheses: -(-2j(j-3)), so:

-2j(j-3)

We multiply parentheses

-2j^2+6j

Back to the equation:

-(-2j^2+6j)


We add all the numbers together, and all the variables

-(-2j^2+6j)+6=0

We get rid of parentheses

2j^2-6j+6=0

a = 2; b = -6; c = +6;
Δ = b2-4ac
Δ = -62-4·2·6
Δ = -12
Delta is less than zero, so there is no solution for the equation