12j-3=13(j-12)+j

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Solution for 12j-3=13(j-12)+j equation: 



12j-3=13(j-12)+j

We move all terms to the left:

12j-3-(13(j-12)+j)=0



We calculate terms in parentheses: -(13(j-12)+j), so:

13(j-12)+j

We add all the numbers together, and all the variables

j+13(j-12)

We multiply parentheses

j+13j-156

We add all the numbers together, and all the variables

14j-156

Back to the equation:

-(14j-156)



We get rid of parentheses

12j-14j+156-3=0

We add all the numbers together, and all the variables

-2j+153=0

We move all terms containing j to the left, all other terms to the right

-2j=-153

j=-153/-2

j=76+1/2

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