12j+68=40j-100

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Solution for 12j+68=40j-100 equation: 



12j+68=40j-100

We move all terms to the left:

12j+68-(40j-100)=0

We get rid of parentheses

12j-40j+100+68=0

We add all the numbers together, and all the variables

-28j+168=0

We move all terms containing j to the left, all other terms to the right

-28j=-168

j=-168/-28

j=+6

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