12g=12((2g/3)-1)+11

Solution for 12g=12((2g/3)-1)+11 equation:

12g=12((2g/3)-1)+11

We move all terms to the left:

12g-(12((2g/3)-1)+11)=0

We add all the numbers together, and all the variables

12g-(12((+2g/3)-1)+11)=0

We multiply all the terms by the denominator


12g*3)-1)+11)-(12((+2g=0

We add all the numbers together, and all the variables

2g+12g*3)-1)+11)-(12((=0

Wy multiply elements

36g^2+2g=0

a = 36; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·36·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*36}=\frac{-4}{72}
=-1/18
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*36}=\frac{0}{72}
=0
$