12d2+29d-8=0

Solution for 12d2+29d-8=0 equation:

12d^2+29d-8=0

a = 12; b = 29; c = -8;
Δ = b2-4ac
Δ = 292-4·12·(-8)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-35}{2*12}=\frac{-64}{24}
=-2+2/3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+35}{2*12}=\frac{6}{24}
=1/4
$