12d-24=2(d-3)+22

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Solution for 12d-24=2(d-3)+22 equation: 



12d-24=2(d-3)+22

We move all terms to the left:

12d-24-(2(d-3)+22)=0



We calculate terms in parentheses: -(2(d-3)+22), so:

2(d-3)+22

We multiply parentheses

2d-6+22

We add all the numbers together, and all the variables

2d+16

Back to the equation:

-(2d+16)



We get rid of parentheses

12d-2d-16-24=0

We add all the numbers together, and all the variables

10d-40=0

We move all terms containing d to the left, all other terms to the right

10d=40

d=40/10

d=4

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