12c-6=3(c+4)

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Solution for 12c-6=3(c+4) equation: 



12c-6=3(c+4)

We move all terms to the left:

12c-6-(3(c+4))=0



We calculate terms in parentheses: -(3(c+4)), so:

3(c+4)

We multiply parentheses

3c+12

Back to the equation:

-(3c+12)



We get rid of parentheses

12c-3c-12-6=0

We add all the numbers together, and all the variables

9c-18=0

We move all terms containing c to the left, all other terms to the right

9c=18

c=18/9

c=2

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