12c-5=9c+22c=

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Solution for 12c-5=9c+22c= equation: 



12c-5=9c+22c=

We move all terms to the left:

12c-5-(9c+22c)=0

We add all the numbers together, and all the variables

12c-(+31c)-5=0

We get rid of parentheses

12c-31c-5=0

We add all the numbers together, and all the variables

-19c-5=0

We move all terms containing c to the left, all other terms to the right

-19c=5

c=5/-19

c=-5/19

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