12b=5(b+2)-3

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Solution for 12b=5(b+2)-3 equation: 



12b=5(b+2)-3

We move all terms to the left:

12b-(5(b+2)-3)=0



We calculate terms in parentheses: -(5(b+2)-3), so:

5(b+2)-3

We multiply parentheses

5b+10-3

We add all the numbers together, and all the variables

5b+7

Back to the equation:

-(5b+7)



We get rid of parentheses

12b-5b-7=0

We add all the numbers together, and all the variables

7b-7=0

We move all terms containing b to the left, all other terms to the right

7b=7

b=7/7

b=1

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