12b=(5+2b)-7

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Solution for 12b=(5+2b)-7 equation: 



12b=(5+2b)-7

We move all terms to the left:

12b-((5+2b)-7)=0

We add all the numbers together, and all the variables

12b-((2b+5)-7)=0



We calculate terms in parentheses: -((2b+5)-7), so:

(2b+5)-7

We get rid of parentheses

2b+5-7

We add all the numbers together, and all the variables

2b-2

Back to the equation:

-(2b-2)



We get rid of parentheses

12b-2b+2=0

We add all the numbers together, and all the variables

10b+2=0

We move all terms containing b to the left, all other terms to the right

10b=-2

b=-2/10

b=-1/5

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