12b2-52b-40=0

Solution for 12b2-52b-40=0 equation:

12b^2-52b-40=0

a = 12; b = -52; c = -40;
Δ = b2-4ac
Δ = -522-4·12·(-40)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-68}{2*12}=\frac{-16}{24}
=-2/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+68}{2*12}=\frac{120}{24}
=5
$