12b-11b=3(b+5)-3(b-3)

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Solution for 12b-11b=3(b+5)-3(b-3) equation: 



12b-11b=3(b+5)-3(b-3)

We move all terms to the left:

12b-11b-(3(b+5)-3(b-3))=0

We add all the numbers together, and all the variables

b-(3(b+5)-3(b-3))=0



We calculate terms in parentheses: -(3(b+5)-3(b-3)), so:

3(b+5)-3(b-3)

We multiply parentheses

3b-3b+15+9

We add all the numbers together, and all the variables

24

Back to the equation:

-(24)



We move all terms containing b to the left, all other terms to the right

b=24

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