12b+8/b+24=4

Solution for 12b+8/b+24=4 equation:

12b+8/b+24=4

We move all terms to the left:

12b+8/b+24-(4)=0


Domain of the equation: b!=0

b∈R


We add all the numbers together, and all the variables

12b+8/b+20=0

We multiply all the terms by the denominator


12b*b+20*b+8=0

We add all the numbers together, and all the variables

20b+12b*b+8=0

Wy multiply elements

12b^2+20b+8=0

a = 12; b = 20; c = +8;
Δ = b2-4ac
Δ = 202-4·12·8
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4}{2*12}=\frac{-24}{24}
=-1
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4}{2*12}=\frac{-16}{24}
=-2/3
$