12=z+(4z+32)

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Solution for 12=z+(4z+32) equation:


Simplifying
12 = z + (4z + 32)

Reorder the terms:
12 = z + (32 + 4z)

Remove parenthesis around (32 + 4z)
12 = z + 32 + 4z

Reorder the terms:
12 = 32 + z + 4z

Combine like terms: z + 4z = 5z
12 = 32 + 5z

Solving
12 = 32 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
12 + -5z = 32 + 5z + -5z

Combine like terms: 5z + -5z = 0
12 + -5z = 32 + 0
12 + -5z = 32

Add '-12' to each side of the equation.
12 + -12 + -5z = 32 + -12

Combine like terms: 12 + -12 = 0
0 + -5z = 32 + -12
-5z = 32 + -12

Combine like terms: 32 + -12 = 20
-5z = 20

Divide each side by '-5'.
z = -4

Simplifying
z = -4

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