12=y+(y(3))

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Solution for 12=y+(y(3)) equation: 



12=y+(y(3))

We move all terms to the left:

12-(y+(y(3)))=0

determiningTheFunctionDomain
-(y+y3)+12=0

We add all the numbers together, and all the variables

-(+y+y^3)+12=0

We get rid of parentheses

-y^3-y+12=0

We do not support eypression: y^3

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