12=7u+4(u-3)

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Solution for 12=7u+4(u-3) equation: 



12=7u+4(u-3)

We move all terms to the left:

12-(7u+4(u-3))=0



We calculate terms in parentheses: -(7u+4(u-3)), so:

7u+4(u-3)

We multiply parentheses

7u+4u-12

We add all the numbers together, and all the variables

11u-12

Back to the equation:

-(11u-12)



We get rid of parentheses

-11u+12+12=0

We add all the numbers together, and all the variables

-11u+24=0

We move all terms containing u to the left, all other terms to the right

-11u=-24

u=-24/-11

u=2+2/11

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