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12=4/5(10g-5)
We move all terms to the left:
12-(4/5(10g-5))=0
Domain of the equation: 5(10g-5))!=0We multiply all the terms by the denominator
g∈R
-(4+12*5(10g-5))=0
We calculate terms in parentheses: -(4+12*5(10g-5)), so:We add all the numbers together, and all the variables
4+12*5(10g-5)
determiningTheFunctionDomain 12*5(10g-5)+4
Wy multiply elements
60g(1+4
Back to the equation:
-(60g(1+4)
-(60g5=0
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