12=4(z-2)

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Solution for 12=4(z-2) equation: 



12=4(z-2)

We move all terms to the left:

12-(4(z-2))=0



We calculate terms in parentheses: -(4(z-2)), so:

4(z-2)

We multiply parentheses

4z-8

Back to the equation:

-(4z-8)



We get rid of parentheses

-4z+8+12=0

We add all the numbers together, and all the variables

-4z+20=0

We move all terms containing z to the left, all other terms to the right

-4z=-20

z=-20/-4

z=+5

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