12=4(2x+4)+68

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Solution for 12=4(2x+4)+68 equation: 



12=4(2x+4)+68

We move all terms to the left:

12-(4(2x+4)+68)=0



We calculate terms in parentheses: -(4(2x+4)+68), so:

4(2x+4)+68

We multiply parentheses

8x+16+68

We add all the numbers together, and all the variables

8x+84

Back to the equation:

-(8x+84)



We get rid of parentheses

-8x-84+12=0

We add all the numbers together, and all the variables

-8x-72=0

We move all terms containing x to the left, all other terms to the right

-8x=72

x=72/-8

x=-9

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