12=3c-3(5c-2c)

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Solution for 12=3c-3(5c-2c) equation: 



12=3c-3(5c-2c)

We move all terms to the left:

12-(3c-3(5c-2c))=0

We add all the numbers together, and all the variables

-(3c-3(+3c))+12=0



We calculate terms in parentheses: -(3c-3(+3c)), so:

3c-3(+3c)

We multiply parentheses

3c-9c

We add all the numbers together, and all the variables

-6c

Back to the equation:

-(-6c)



We get rid of parentheses

6c+12=0

We move all terms containing c to the left, all other terms to the right

6c=-12

c=-12/6

c=-2

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