12=3(u-8)+6u

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Solution for 12=3(u-8)+6u equation: 



12=3(u-8)+6u

We move all terms to the left:

12-(3(u-8)+6u)=0



We calculate terms in parentheses: -(3(u-8)+6u), so:

3(u-8)+6u

We add all the numbers together, and all the variables

6u+3(u-8)

We multiply parentheses

6u+3u-24

We add all the numbers together, and all the variables

9u-24

Back to the equation:

-(9u-24)



We get rid of parentheses

-9u+24+12=0

We add all the numbers together, and all the variables

-9u+36=0

We move all terms containing u to the left, all other terms to the right

-9u=-36

u=-36/-9

u=+4

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