12=3(b-6)

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Solution for 12=3(b-6) equation: 



12=3(b-6)

We move all terms to the left:

12-(3(b-6))=0



We calculate terms in parentheses: -(3(b-6)), so:

3(b-6)

We multiply parentheses

3b-18

Back to the equation:

-(3b-18)



We get rid of parentheses

-3b+18+12=0

We add all the numbers together, and all the variables

-3b+30=0

We move all terms containing b to the left, all other terms to the right

-3b=-30

b=-30/-3

b=+10

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