12=2b2/2

Solution for 12=2b2/2 equation:

12=2b^2/2

We move all terms to the left:

12-(2b^2/2)=0

We get rid of parentheses

-2b^2/2+12=0

We multiply all the terms by the denominator


-2b^2+12*2=0

We add all the numbers together, and all the variables

-2b^2+24=0

a = -2; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·(-2)·24
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*-2}=\frac{0-8\sqrt{3}}{-4}
=-\frac{8\sqrt{3}}{-4}
=-\frac{2\sqrt{3}}{-1}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*-2}=\frac{0+8\sqrt{3}}{-4}
=\frac{8\sqrt{3}}{-4}
=\frac{2\sqrt{3}}{-1}
$