12=2/5(5k+35)-8

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Solution for 12=2/5(5k+35)-8 equation: 



12=2/5(5k+35)-8

We move all terms to the left:

12-(2/5(5k+35)-8)=0



Domain of the equation: 5(5k+35)-8)!=0

k∈R



We multiply all the terms by the denominator


-(2+12*5(5k+35)-8)=0



We calculate terms in parentheses: -(2+12*5(5k+35)-8), so:

2+12*5(5k+35)-8

determiningTheFunctionDomain
12*5(5k+35)+2-8

We add all the numbers together, and all the variables

12*5(5k+35)-6

Wy multiply elements

60k(5-6

Back to the equation:

-(60k(5-6)



We add all the numbers together, and all the variables

-(60k(-1)=0



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