12=2(4x-8)+12(x-1)

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Solution for 12=2(4x-8)+12(x-1) equation: 



12=2(4x-8)+12(x-1)

We move all terms to the left:

12-(2(4x-8)+12(x-1))=0



We calculate terms in parentheses: -(2(4x-8)+12(x-1)), so:

2(4x-8)+12(x-1)

We multiply parentheses

8x+12x-16-12

We add all the numbers together, and all the variables

20x-28

Back to the equation:

-(20x-28)



We get rid of parentheses

-20x+28+12=0

We add all the numbers together, and all the variables

-20x+40=0

We move all terms containing x to the left, all other terms to the right

-20x=-40

x=-40/-20

x=+2

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