12=2(3x+1)+22

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Solution for 12=2(3x+1)+22 equation: 



12=2(3x+1)+22

We move all terms to the left:

12-(2(3x+1)+22)=0



We calculate terms in parentheses: -(2(3x+1)+22), so:

2(3x+1)+22

We multiply parentheses

6x+2+22

We add all the numbers together, and all the variables

6x+24

Back to the equation:

-(6x+24)



We get rid of parentheses

-6x-24+12=0

We add all the numbers together, and all the variables

-6x-12=0

We move all terms containing x to the left, all other terms to the right

-6x=12

x=12/-6

x=-2

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