12=2(3+6m)+6(4m+1)

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Solution for 12=2(3+6m)+6(4m+1) equation: 



12=2(3+6m)+6(4m+1)

We move all terms to the left:

12-(2(3+6m)+6(4m+1))=0

We add all the numbers together, and all the variables

-(2(6m+3)+6(4m+1))+12=0



We calculate terms in parentheses: -(2(6m+3)+6(4m+1)), so:

2(6m+3)+6(4m+1)

We multiply parentheses

12m+24m+6+6

We add all the numbers together, and all the variables

36m+12

Back to the equation:

-(36m+12)



We get rid of parentheses

-36m-12+12=0

We add all the numbers together, and all the variables

-36m=0

m=0/-36

m=0

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