12=-8(c-12)-4

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Solution for 12=-8(c-12)-4 equation: 



12=-8(c-12)-4

We move all terms to the left:

12-(-8(c-12)-4)=0



We calculate terms in parentheses: -(-8(c-12)-4), so:

-8(c-12)-4

We multiply parentheses

-8c+96-4

We add all the numbers together, and all the variables

-8c+92

Back to the equation:

-(-8c+92)



We get rid of parentheses

8c-92+12=0

We add all the numbers together, and all the variables

8c-80=0

We move all terms containing c to the left, all other terms to the right

8c=80

c=80/8

c=10

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