12=-7y+3(y-4)

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Solution for 12=-7y+3(y-4) equation: 



12=-7y+3(y-4)

We move all terms to the left:

12-(-7y+3(y-4))=0



We calculate terms in parentheses: -(-7y+3(y-4)), so:

-7y+3(y-4)

We multiply parentheses

-7y+3y-12

We add all the numbers together, and all the variables

-4y-12

Back to the equation:

-(-4y-12)



We get rid of parentheses

4y+12+12=0

We add all the numbers together, and all the variables

4y+24=0

We move all terms containing y to the left, all other terms to the right

4y=-24

y=-24/4

y=-6

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