12=-4(b-3)+4b

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Solution for 12=-4(b-3)+4b equation: 



12=-4(b-3)+4b

We move all terms to the left:

12-(-4(b-3)+4b)=0



We calculate terms in parentheses: -(-4(b-3)+4b), so:

-4(b-3)+4b

We add all the numbers together, and all the variables

4b-4(b-3)

We multiply parentheses

4b-4b+12

We add all the numbers together, and all the variables

12

Back to the equation:

-(12)



We add all the numbers together, and all the variables

=0

b=0/1

b=0

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