12=-3(2-2r)(-2r+2)

Solution for 12=-3(2-2r)(-2r+2) equation:

12=-3(2-2r)(-2r+2)

We move all terms to the left:

12-(-3(2-2r)(-2r+2))=0

We add all the numbers together, and all the variables

-(-3(-2r+2)(-2r+2))+12=0

We multiply parentheses ..

-(-3(+4r^2-4r-4r+4))+12=0


We calculate terms in parentheses: -(-3(+4r^2-4r-4r+4)), so:

-3(+4r^2-4r-4r+4)

We multiply parentheses

-12r^2+12r+12r-12

We add all the numbers together, and all the variables

-12r^2+24r-12

Back to the equation:

-(-12r^2+24r-12)


We get rid of parentheses

12r^2-24r+12+12=0

We add all the numbers together, and all the variables

12r^2-24r+24=0

a = 12; b = -24; c = +24;
Δ = b2-4ac
Δ = -242-4·12·24
Δ = -576
Delta is less than zero, so there is no solution for the equation