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12=(x-5)+(4x-3)
We move all terms to the left:
12-((x-5)+(4x-3))=0
We calculate terms in parentheses: -((x-5)+(4x-3)), so:We get rid of parentheses
(x-5)+(4x-3)
We get rid of parentheses
x+4x-5-3
We add all the numbers together, and all the variables
5x-8
Back to the equation:
-(5x-8)
-5x+8+12=0
We add all the numbers together, and all the variables
-5x+20=0
We move all terms containing x to the left, all other terms to the right
-5x=-20
x=-20/-5
x=+4
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