12=(3x-4)+x

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Solution for 12=(3x-4)+x equation: 



12=(3x-4)+x

We move all terms to the left:

12-((3x-4)+x)=0



We calculate terms in parentheses: -((3x-4)+x), so:

(3x-4)+x

We add all the numbers together, and all the variables

x+(3x-4)

We get rid of parentheses

x+3x-4

We add all the numbers together, and all the variables

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

-4x+4+12=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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