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12=(3/4)x+6
We move all terms to the left:
12-((3/4)x+6)=0
Domain of the equation: 4)x+6)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+3/4)x+6)+12=0
We multiply all the terms by the denominator
-((+3+12*4)x+6)=0
We calculate terms in parentheses: -((+3+12*4)x+6), so:We get rid of parentheses
(+3+12*4)x+6
We add all the numbers together, and all the variables
51x+6
Back to the equation:
-(51x+6)
-51x-6=0
We move all terms containing x to the left, all other terms to the right
-51x=6
x=6/-51
x=-2/17
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