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12=(2+c)-(4+2c)
We move all terms to the left:
12-((2+c)-(4+2c))=0
We add all the numbers together, and all the variables
-((c+2)-(2c+4))+12=0
We calculate terms in parentheses: -((c+2)-(2c+4)), so:We get rid of parentheses
(c+2)-(2c+4)
We get rid of parentheses
c-2c+2-4
We add all the numbers together, and all the variables
-1c-2
Back to the equation:
-(-1c-2)
1c+2+12=0
We add all the numbers together, and all the variables
c+14=0
We move all terms containing c to the left, all other terms to the right
c=-14
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