128=8(7+2n)+2n

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Solution for 128=8(7+2n)+2n equation: 



128=8(7+2n)+2n

We move all terms to the left:

128-(8(7+2n)+2n)=0

We add all the numbers together, and all the variables

-(8(2n+7)+2n)+128=0



We calculate terms in parentheses: -(8(2n+7)+2n), so:

8(2n+7)+2n

We add all the numbers together, and all the variables

2n+8(2n+7)

We multiply parentheses

2n+16n+56

We add all the numbers together, and all the variables

18n+56

Back to the equation:

-(18n+56)



We get rid of parentheses

-18n-56+128=0

We add all the numbers together, and all the variables

-18n+72=0

We move all terms containing n to the left, all other terms to the right

-18n=-72

n=-72/-18

n=+4

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