128=8(1-3k)

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Solution for 128=8(1-3k) equation: 



128=8(1-3k)

We move all terms to the left:

128-(8(1-3k))=0

We add all the numbers together, and all the variables

-(8(-3k+1))+128=0



We calculate terms in parentheses: -(8(-3k+1)), so:

8(-3k+1)

We multiply parentheses

-24k+8

Back to the equation:

-(-24k+8)



We get rid of parentheses

24k-8+128=0

We add all the numbers together, and all the variables

24k+120=0

We move all terms containing k to the left, all other terms to the right

24k=-120

k=-120/24

k=-5

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