128=41+3y

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Solution for 128=41+3y equation: 



128=41+3y

We move all terms to the left:

128-(41+3y)=0

We add all the numbers together, and all the variables

-(3y+41)+128=0

We get rid of parentheses

-3y-41+128=0

We add all the numbers together, and all the variables

-3y+87=0

We move all terms containing y to the left, all other terms to the right

-3y=-87

y=-87/-3

y=+29

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