128=3x+5(3x-4)

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Solution for 128=3x+5(3x-4) equation: 



128=3x+5(3x-4)

We move all terms to the left:

128-(3x+5(3x-4))=0



We calculate terms in parentheses: -(3x+5(3x-4)), so:

3x+5(3x-4)

We multiply parentheses

3x+15x-20

We add all the numbers together, and all the variables

18x-20

Back to the equation:

-(18x-20)



We get rid of parentheses

-18x+20+128=0

We add all the numbers together, and all the variables

-18x+148=0

We move all terms containing x to the left, all other terms to the right

-18x=-148

x=-148/-18

x=8+2/9

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