128=3b+4(1+7b)

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Solution for 128=3b+4(1+7b) equation:


Simplifying
128 = 3b + 4(1 + 7b)
128 = 3b + (1 * 4 + 7b * 4)
128 = 3b + (4 + 28b)

Reorder the terms:
128 = 4 + 3b + 28b

Combine like terms: 3b + 28b = 31b
128 = 4 + 31b

Solving
128 = 4 + 31b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-31b' to each side of the equation.
128 + -31b = 4 + 31b + -31b

Combine like terms: 31b + -31b = 0
128 + -31b = 4 + 0
128 + -31b = 4

Add '-128' to each side of the equation.
128 + -128 + -31b = 4 + -128

Combine like terms: 128 + -128 = 0
0 + -31b = 4 + -128
-31b = 4 + -128

Combine like terms: 4 + -128 = -124
-31b = -124

Divide each side by '-31'.
b = 4

Simplifying
b = 4

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