128=2(7m+8)

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Solution for 128=2(7m+8) equation: 



128=2(7m+8)

We move all terms to the left:

128-(2(7m+8))=0



We calculate terms in parentheses: -(2(7m+8)), so:

2(7m+8)

We multiply parentheses

14m+16

Back to the equation:

-(14m+16)



We get rid of parentheses

-14m-16+128=0

We add all the numbers together, and all the variables

-14m+112=0

We move all terms containing m to the left, all other terms to the right

-14m=-112

m=-112/-14

m=+8

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