128=10(1-a)-2

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Solution for 128=10(1-a)-2 equation: 



128=10(1-a)-2

We move all terms to the left:

128-(10(1-a)-2)=0

We add all the numbers together, and all the variables

-(10(-1a+1)-2)+128=0



We calculate terms in parentheses: -(10(-1a+1)-2), so:

10(-1a+1)-2

We multiply parentheses

-10a+10-2

We add all the numbers together, and all the variables

-10a+8

Back to the equation:

-(-10a+8)



We get rid of parentheses

10a-8+128=0

We add all the numbers together, and all the variables

10a+120=0

We move all terms containing a to the left, all other terms to the right

10a=-120

a=-120/10

a=-12

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