128=(10+2x)

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Solution for 128=(10+2x) equation:



128=(10+2x)
We move all terms to the left:
128-((10+2x))=0
We add all the numbers together, and all the variables
-((2x+10))+128=0
We calculate terms in parentheses: -((2x+10)), so:
(2x+10)
We get rid of parentheses
2x+10
Back to the equation:
-(2x+10)
We get rid of parentheses
-2x-10+128=0
We add all the numbers together, and all the variables
-2x+118=0
We move all terms containing x to the left, all other terms to the right
-2x=-118
x=-118/-2
x=+59

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