126=2x+x+(10+x)

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Solution for 126=2x+x+(10+x) equation: 



126=2x+x+(10+x)

We move all terms to the left:

126-(2x+x+(10+x))=0

We add all the numbers together, and all the variables

-(2x+x+(x+10))+126=0



We calculate terms in parentheses: -(2x+x+(x+10)), so:

2x+x+(x+10)

We add all the numbers together, and all the variables

3x+(x+10)

We get rid of parentheses

3x+x+10

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We get rid of parentheses

-4x-10+126=0

We add all the numbers together, and all the variables

-4x+116=0

We move all terms containing x to the left, all other terms to the right

-4x=-116

x=-116/-4

x=+29

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