125=(t-28)+(t+11)

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Solution for 125=(t-28)+(t+11) equation: 



125=(t-28)+(t+11)

We move all terms to the left:

125-((t-28)+(t+11))=0



We calculate terms in parentheses: -((t-28)+(t+11)), so:

(t-28)+(t+11)

We get rid of parentheses

t+t-28+11

We add all the numbers together, and all the variables

2t-17

Back to the equation:

-(2t-17)



We get rid of parentheses

-2t+17+125=0

We add all the numbers together, and all the variables

-2t+142=0

We move all terms containing t to the left, all other terms to the right

-2t=-142

t=-142/-2

t=+71

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