122=x+(4x-3)

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Solution for 122=x+(4x-3) equation: 



122=x+(4x-3)

We move all terms to the left:

122-(x+(4x-3))=0



We calculate terms in parentheses: -(x+(4x-3)), so:

x+(4x-3)

We get rid of parentheses

x+4x-3

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We get rid of parentheses

-5x+3+122=0

We add all the numbers together, and all the variables

-5x+125=0

We move all terms containing x to the left, all other terms to the right

-5x=-125

x=-125/-5

x=+25

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