122=4z-2+3z+4z-2+3z

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Solution for 122=4z-2+3z+4z-2+3z equation: 



122=4z-2+3z+4z-2+3z

We move all terms to the left:

122-(4z-2+3z+4z-2+3z)=0

We add all the numbers together, and all the variables

-(14z-4)+122=0

We get rid of parentheses

-14z+4+122=0

We add all the numbers together, and all the variables

-14z+126=0

We move all terms containing z to the left, all other terms to the right

-14z=-126

z=-126/-14

z=+9

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